Find an equation of the tangent line to the curve at the given point. So I use the chain rule for this don't I? Pretty much stuck from here. Thanks in advance.
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Originally Posted by cloudzer0 Find an equation of the tangent line to the curve at the given point. So I use the chain rule for this don't I? Pretty much stuck from here. Thanks in advance. From here, substitute x=0 into the derivative: Plug the slope and the point into the point-slope form of a line: . Hope this helped you out!
Originally Posted by cloudzer0 Find an equation of the tangent line to the curve at the given point. So I use the chain rule for this don't I? Pretty much stuck from here. Thanks in advance. So now we need to the slope. To find the slope we evaluate the derivative at x=0 Now we use the point slope formula Yeah!
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