Find an equation of the tangent line to the curve at the given point.
$\displaystyle y = (1+2x)^{10} , (0,1)$
So I use the chain rule for this don't I?
$\displaystyle y' = 10(1+2x)^{9}(2)$
Pretty much stuck from here.
Thanks in advance.
Find an equation of the tangent line to the curve at the given point.
$\displaystyle y = (1+2x)^{10} , (0,1)$
So I use the chain rule for this don't I?
$\displaystyle y' = 10(1+2x)^{9}(2)$
Pretty much stuck from here.
Thanks in advance.