A particle moves as at speed of 2.5 m/s in the +x-direction. Upon reaching the origin, the particle receives a continuous constant acceleration of 0.75 m/s2 in the -y-direction. What is the position of the particle 4.0 s later?

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- Jun 27th 2006, 08:49 AMCeliaAparticle moves.......
A particle moves as at speed of 2.5 m/s in the +x-direction. Upon reaching the origin, the particle receives a continuous constant acceleration of 0.75 m/s2 in the -y-direction. What is the position of the particle 4.0 s later?

- Jun 27th 2006, 09:04 AMJameson
So once the particle is at (0,0) it moves for 4 seconds. The x-component has no acceleration so this is just (2.5 m/s) * 4s.

To find the y-component, use the formula $\displaystyle d=v_{0}t+\frac{1}{2}at^2$. v_0 is zero in this case though. - Jan 3rd 2008, 03:31 PMjbookerbubble