How do i solve this: What is the Cartesian equation for the region represented by Re((8-i) z +3) = 0 Thanks
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Hello, Originally Posted by taurus How do i solve this: What is the Cartesian equation for the region represented by Re((8-i) z +3) = 0 Thanks Write $\displaystyle z=x+iy$, x and y are real numbers. -> $\displaystyle (8-i)z=(8x+y)+i(y-x)$ -> $\displaystyle (8-i)z+3=(8x+y+3)+i(y-x)$ --> $\displaystyle Re((8-i)z+3)=8x+y+3$ ----> $\displaystyle \boxed{8x+y+3=0}$
So your first step you expanded brackets yes? so > (8-i)z > (8-i)(x+iy) > 8x + 8y - ix - iy = 8(x+y) - i(x-y) Which doesnt look like yours. What am i doing wrong?
Originally Posted by taurus So your first step you expanded brackets yes? so > (8-i)z > (8-i)(x+iy) > 8x + 8y - ix - iy = 8(x+y) - i(x+y) Which doesnt look like yours. What am i doing wrong? I'm doing wrong Sorry, a little mistake. You're right
Last edited by Moo; May 12th 2008 at 03:35 AM.
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