1. ## intergrate (x^2-2x+4)/x

How do I intergrate:

(x^2-2x+4)/x

I know it should be easy, can I be pointed in the direction of some information on this please?

2. Originally Posted by dangerous_dave
How do I intergrate:

(x^2-2x+4)/x

I know it should be easy, can I be pointed in the direction of some information on this please?
Break it up into x^2/x - 2x/x + 4/x.

This will give you x - 2 + 4/x. I think you can integrate that?

3. Originally Posted by dangerous_dave
How do I intergrate:

(x^2-2x+4)/x

I know it should be easy, can I be pointed in the direction of some information on this please?
$\int\frac{x^2-2x+4}{x}dx=\int\bigg[x-2+\frac{4}{x}\bigg]dx=\frac{x^2}{2}-2x+4\ln(x)+C$

4. Oh that does make it easy . Thanks for your help.

5. Originally Posted by dangerous_dave
Oh that does make it easy . Thanks for your help.
Don't worry we all miss the easy things once in a while