How do I intergrate: (x^2-2x+4)/x I know it should be easy, can I be pointed in the direction of some information on this please?
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Originally Posted by dangerous_dave How do I intergrate: (x^2-2x+4)/x I know it should be easy, can I be pointed in the direction of some information on this please? Break it up into x^2/x - 2x/x + 4/x. This will give you x - 2 + 4/x. I think you can integrate that?
Originally Posted by dangerous_dave How do I intergrate: (x^2-2x+4)/x I know it should be easy, can I be pointed in the direction of some information on this please? $\displaystyle \int\frac{x^2-2x+4}{x}dx=\int\bigg[x-2+\frac{4}{x}\bigg]dx=\frac{x^2}{2}-2x+4\ln(x)+C$
Oh that does make it easy . Thanks for your help.
Originally Posted by dangerous_dave Oh that does make it easy . Thanks for your help. Don't worry we all miss the easy things once in a while
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