What is the basic process of finding the average value for this problem. Find the average value of the function f(x)= sin(x) on the interval [0, pi]
Average value of $\displaystyle f(x)$ on $\displaystyle [a,b]$ is $\displaystyle \frac{1}{b-a}\int_a^{b}f(x)dx$
Therefore for $\displaystyle f(x)=\sin(x)$ and $\displaystyle [0,\pi]$ youd have average value is
$\displaystyle \frac{1}{\pi-0}\int_0^{\pi}\sin(x)dx=\frac{1}{\pi}\bigg[-\cos(x)\bigg]\bigg|_0^{\pi}=\frac{2}{\pi}$