Show that the curve with vector equation $\displaystyle r(t) = <2 cos^2(t), sin(2t), 2sin(t)>$ is the curve of intersection of the surfaces $\displaystyle (x-1)^2+y^2 = 1$ and $\displaystyle x^2 + y^2 + z^2 = 4$. Use this fact to sketch the curve.

Im completely lost here!(Angry)