A particle moves along the curve given by s = sqrt(t+1). Find the acceleration at 2 seconds. A particle moves a long a curve.. that means it's giving me position function? And I need to take the derivative twice to get to acceleration?
Also I am working on a review hand out that my professor gave us, so instead of creating a bunch of threads could I just make one thread and post there any time I come to a problem I need explained?
Well I took the derivative twice.
v = 1/(2 )
a = -1/(4 )
I plug in 2 for the acceleration function
My problem is the answer key says it's supposed to come out to -1/32, and I have -1/4sqrt3. Where'd I go wrong?