integrate 1/(x^3 + 2x^2- x-2) dx

i know have to use partial fractions.

A/ (x^2-1) + B /(x+2) = 1/ (x^3 + 2x^2- x-2)

and found B =1/3 and A =1/3 or 1 (don't know which one to use so i used A= 1/3)

after integrate i got ln(3x^2-3) + ln(3x+6) not sure if it is right..but i have a feeling that it's wrong. Help!