Hi all, I need to differentiate this expression twice to find a new expression when t = 0.6 y = 3sin (5 pi t) t = 0.6 (pi = 3.14) Any help appreciated.
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Originally Posted by astrostar Hi all, I need to differentiate this expression twice to find a new expression when t = 0.6 y = 3sin (5 pi t) t = 0.6 (pi = 3.14) Any help appreciated. $\displaystyle \frac{dy}{dx} = 15\pi \cos{(5\pi t)}$ $\displaystyle \frac{d^2y}{dx^2}$ = $\displaystyle -75\pi ^2 \sin{(5\pi t)}$
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