1) x^3*(x^2-1)^(1/3) dx 2) 1/(xln(x^3)) dx Appreciate all help given. Thank you.
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2. Let and remember that: 1. Note that: and now try a substitution
Hello, Originally Posted by Hibijibi 1) x^3*(x^2-1)^(1/3) dx Integrate by parts : etc...
So I rewrite the ln function as 1/ (x (3*ln(x))) and use u to equal lnx, and u'= 1/x, and then what? Edit: i got the function down to 1/3 intergral of 1/u du, and how do I get past this?
Originally Posted by Hibijibi So I rewrite the ln function as 1/ (x (3*ln(x))) and use u to equal lnx, and u'= 1/x, and then what? -> do the substitutions
Thanks, I got it. Except I I used du = 1/x dx, since 1/x dx is in the function already and I solved. Appreciate it!
Originally Posted by Hibijibi Thanks, I got it. Except I I used du = 1/x dx, since 1/x dx is in the function already and I solved. Appreciate it! I'm sorry about it... Actually I'm a bit lost concerning the way people learn how to do substitutions
Haha everyone to their own right? Thank you very much Moo! *hugs*
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