1) x^3*(x^2-1)^(1/3) dx

2) 1/(xln(x^3)) dx

Appreciate all help given. Thank you.

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- May 8th 2008, 06:27 AMHibijibiTwo Integrals
1) x^3*(x^2-1)^(1/3) dx

2) 1/(xln(x^3)) dx

Appreciate all help given. Thank you. - May 8th 2008, 06:30 AMPaulRS
2. Let and remember that:

1. Note that:

and now try a substitution - May 8th 2008, 06:35 AMMoo
- May 8th 2008, 08:10 AMHibijibi
So I rewrite the ln function as 1/ (x (3*ln(x))) and use u to equal lnx, and u'= 1/x, and then what?

Edit: i got the function down to 1/3 intergral of 1/u du, and how do I get past this? - May 8th 2008, 08:11 AMMoo
- May 8th 2008, 08:33 AMHibijibi
Thanks, I got it. Except I I used du = 1/x dx, since 1/x dx is in the function already and I solved. Appreciate it!

- May 8th 2008, 08:36 AMMoo
- May 8th 2008, 08:37 AMHibijibi
Haha everyone to their own right? :) Thank you very much Moo! *hugs*