Q: .

(a)Evaluate .

(b) Find an equation of the tangent to the curve with equation at the point where .

__________________

I've done part (a) but struggling with part (b). May I have some help please. (Smile)

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- May 8th 2008, 05:57 AMSimplicityTrigonometry Function Derivative
Q: .

(a)Evaluate .

(b) Find an equation of the tangent to the curve with equation at the point where .

__________________

I've done part (a) but struggling with part (b). May I have some help please. (Smile) - May 8th 2008, 06:04 AMflyingsquirrel
Hi

The equation of the tangent to the curve at a point is . In your case, it becomes - May 8th 2008, 06:08 AMSimplicity
But...I still don't get it very well. I understand that the coordinates to consider is . Can someone work out the gradient? I think I might have got that wrong.

- May 8th 2008, 06:10 AMMoo
- May 8th 2008, 06:20 AMGusbob
Another way of getting the gradient:

Gradient of Function y = f'(x) is

but y = arcsin(x)

at

=