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Math Help - Intro to Derivatives

  1. #1
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    Intro to Derivatives

    Find the equation of the tangent to the curve y = \frac {x^2}{x^2 + 1} at  x = 1

     y' = \frac {2x}{(x^2 + 1)^2}

     f'(1) = \frac {1}{2}

     f(1) = \frac {1}{2}

    \frac {1}{2} = \frac {1}{2} x + b

    0 = b

    Therefore, y = \frac {1}{2} x


    Textbook Answer: x - 2y = 0 .... what did I do wrong?
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Macleef View Post
    Find the equation of the tangent to the curve y = \frac {x^2}{x^2 + 1} at  x = 1

     y' = \frac {2x}{(x^2 + 1)^2}

     f'(1) = \frac {1}{2}

     f(1) = \frac {1}{2}

    \frac {1}{2} = \frac {1}{2} x + b

    0 = b

    Therefore, y = \frac {1}{2} x


    Textbook Answer: x - 2y = 0 .... what did I do wrong?
    Um...nothing

    y = (1/2)x

    => 2y = x

    => 0 = x - 2y

    the textbook just has the equation in standard form, that's all
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