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Thread: Fraction Integration

  1. May 7th 2008, 11:06 AM #1
    Simplicity
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    Fraction Integration

    Q: \displaystyle\int^1_0 \frac{1}{3+t^2} \, \mathrm{d}t

    This is a follow on after I've substituted the t value that they asked for. Can someone do this? Thanks in advance.
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  2. May 7th 2008, 11:13 AM #2
    Moo
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    Quote Originally Posted by Air View Post
    Q: \displaystyle\int^1_0 \frac{1}{3+t^2} \, \mathrm{d}t

    This is a follow on after I've substituted the t value that they asked for. Can someone do this? Thanks in advance.
    Hello,

    \frac{1}{3+t^2}=\frac 13 \cdot \frac{1}{1+(t/\sqrt{3})^2}, right ?

    Substitute u=\frac{t}{\sqrt{3}}
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