Q: $\displaystyle \displaystyle\int^1_0 \frac{1}{3+t^2} \, \mathrm{d}t$ This is a follow on after I've substituted the $\displaystyle t$ value that they asked for. Can someone do this? Thanks in advance.
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Originally Posted by Air Q: $\displaystyle \displaystyle\int^1_0 \frac{1}{3+t^2} \, \mathrm{d}t$ This is a follow on after I've substituted the $\displaystyle t$ value that they asked for. Can someone do this? Thanks in advance. Hello, $\displaystyle \frac{1}{3+t^2}=\frac 13 \cdot \frac{1}{1+(t/\sqrt{3})^2}$, right ? Substitute $\displaystyle u=\frac{t}{\sqrt{3}}$
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