1. ## Convergence of Series

Determine if the following series converge or diverge.

a) the sum from n=1 to infinity of [n/3n+1]^2n

b) the sum from n=2 to infinity of [1/(n(ln)^1/2)]

I don't know what test to use with this series (comparison, ratio, integral etc)?

2. Hi

Originally Posted by kithy
The comparison test works : $0\leq \frac{n}{3n+1}=\frac{1}{3+\frac{1}{n}}\leq \frac{1}{3}$
You can use integrals : $\int \frac{1}{t \sqrt{\ln t}} \,\mathrm{d}t=2\int \frac{u'(t)}{2\sqrt{u(t)}} \, \mathrm{d}t$ with $u(t)=\ln t$ can be quite easily evaluated.