Integration problem

• May 7th 2008, 04:21 AM
geton
Integration problem
Show that with limits pi/3 – pi/2, ∫ sin x [(1 + cos x) / (1 - cos x)] dx = ln 4 -1/2.

How can I do this?
• May 7th 2008, 04:33 AM
mr fantastic
Quote:

Originally Posted by geton
Show that with limits pi/3 – pi/2, ∫ sin x [(1 + cos x) / (1 - cos x)] dx = ln 4 -1/2.

How can I do this?

Substitute $u = \cos x$ and $dx = - \frac{du}{\sin x}$. Make sure to substitute for the integral terminals as well.
• May 7th 2008, 06:03 AM
geton
Quote:

Originally Posted by mr fantastic
Substitute $u = \cos x$ and $dx = - \frac{du}{\sin x}$. Make sure to substitute for the integral terminals as well.

Thank you so much.