I have to turn this in to polar the double integral (x^2+y^2 )^(3/2) from o to 3 and Sqrt(9-x^2) I THINK THE ANSWER IS (243PI /10)
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Originally Posted by cchyfly I have to turn this in to polar the double integral (x^2+y^2 )^(3/2) from o to 3 and Sqrt(9-x^2) I THINK THE ANSWER IS (243PI /10) is the integral of over the first quadrant of the interior of the circle , so: RonL
so actually in the last step it is r^4 and then evaluate the integral
Originally Posted by cchyfly so actually in the last step it is r^4 and then evaluate the integral Yes, I left it in the form I did so you could more easily see where things came from. RonL
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