use a trigonometric substitution to find integral of 1/(1+3x^2)^3/2 between limits 0 and 1. I think you have to use tan or sin not quite sure how though.
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Originally Posted by i_zz_y_ill use a trigonometric substitution to find integral of 1/(1+3x^2)^3/2 between limits 0 and 1. I think you have to use tan or sin not quite sure how though. let now continue with the substitution process we use tan because we are using the know your trig identities
thanks but cant see how that works. No doubt ur wright but I still can't do it..
You can leave This changes your limits of integration to 0 to Pi/3. Making the subs will whittle it down to:
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