http://i31.tinypic.com/2qcp7r6.png

There is no answer in my textbook for this question.

Please show a step by step solution so I could follow through...

Here's what I've done so far:

Now what?

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- May 4th 2008, 12:48 PMMacleefIntro to Derivatives - Quotient Rule
http://i31.tinypic.com/2qcp7r6.png

There is no answer in my textbook for this question.

Please show a step by step solution so I could follow through...

Here's what I've done so far:

Now what? - May 4th 2008, 12:51 PMo_O
You know that derivatives essentially represent the slopes of a function. So, if you were to have tangents with a negative slope, f'(x) must be

**negative**.

If f(x) does not have any negative tangents, that must mean f'(x) is never less than 0. Does this happen in your expression for f'(x)? - May 4th 2008, 01:34 PMMacleef
Yes, it doesn't have any negative tangents because the denominator will always be positive and the numerator is a constant positive value?

OT: When you're finding the x values to substitute in the original equation, do you solve for the numerator or denominator?

For example;

Original Equation:

- May 4th 2008, 01:35 PMo_O
(Clapping) .. I'm assuming you took the derivative right :p