Q: $\displaystyle \displaystyle\int \frac{1}{\mathrm{sinh}x + 2 \mathrm{cosh}x} \, \mathrm{d}x$

Would I change it to $\displaystyle e^x$. When I did, I got up to $\displaystyle \displaystyle\int \frac{2}{3e^x + e^{-x}} \, \mathrm{d}x$ but didn't know how to proceed further. Can someone show me how you would have done the original question. Thanks in advance.