Q: Given that , where is a constant, show that .

My method:

But that isn't what they require. What do I do? (Headbang) Thanks in advance for the help.

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- May 4th 2008, 01:49 AMSimplicityDifferentiation (Show That Question)
Q: Given that , where is a constant, show that .

My method:

But that isn't what they require. What do I do? (Headbang) Thanks in advance for the help. - May 4th 2008, 02:18 AMMoo
Yop,

Quote:

04/05/08: Today, I have made many threads for question. Thanks for all the help!

Well, keep

Hence,

From here, you can get and :) - May 4th 2008, 02:22 AMJhevon
- May 7th 2008, 11:37 AMSimplicity

But where would I go from here? Finding the second derivative may be difficult. :confused: - May 7th 2008, 11:50 AMTheEmptySet
- May 7th 2008, 11:54 AMChris L T521
- May 7th 2008, 01:01 PMbobak
I believe you meant to say the chain rule. and using the quotient rule for this question is long and pointless

This is slightly off topic, but seeing as Airs question has already been answered I doubt anyone will mind.

Just have a comment on your signature, you do realise that is multi-valued, I'll give an alternative proof of what you have written in your signature.

you can write as for any integer n.

so becomes

Bobak - May 7th 2008, 01:10 PMChris L T521
I agree that the quotient rule is long and pointless, but it may be good to know that it can be done various ways. However, I did mean Power Rule. When we differentiate it, we end up using the chain rule any, for both the power rule and quotient rule.

Thanks for the input on the signature. Your adjustments to it somewhat makes sense.