Two handy identites to know are:
and
Another one handy to know is the identity
So, you have
Q show that 1/(1-e^jx) = 1/2(1+jcot(x/2)) where x=theta,sorry bwt x
the first line of woking is to answer ( e^-jx/2 ) / ( (e^-jx/2 - e^jx/2 )
but how does 1 = e^-jx/2
could someone show me how to get ans pls???