How do I find the area of the region in one loop of the curve that has polar equation r^2 = 3 cos^2(theta) - 9 sin^2(theta) ???
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Polar integration is
You already have r^2.
The area of half a loop in the first quadrant is
Integrate and multiply by 2.
Last edited by galactus; Nov 24th 2008 at 05:38 AM.
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