How do I find the area of the region in one loop of the curve that has polar equation r^2 = 3 cos^2(theta) - 9 sin^2(theta) ???
Follow Math Help Forum on Facebook and Google+
Polar integration is You already have r^2. The area of half a loop in the first quadrant is Integrate and multiply by 2.
Last edited by galactus; Nov 24th 2008 at 05:38 AM.
View Tag Cloud