Thread: Easy question: i'm new too calc. (urgent)

y= u^5 +u^3

u= 3/v - 4v

v= 3 - x^2

Use the chain rule in Leibniz notation to find (dy/dx) when x = 2

Text gives the solution: -48608

do i use:

(dy/dx) = (dy/du)(du/dv)(dv/dx) because when I do, I don't get the right answer.

Originally Posted by white_cap

y= u^5 +u^3

u= 3/v - 4v

v= 3 - x^2

Use the chain rule in Leibniz notation to find (dy/dx) when x = 2

Text gives the solution: -48608

do i use:

(dy/dx) = (dy/du)(du/dv)(dv/dx) because when I do, I don't get the right answer.

you do use the chain rule, but first you have to substitute to get your function in terms of x

then distrubute


y= u^5 +u^3

now u can differentiate this function using the chain rule in terms of

Well take the derivative:

(Just the application of the power rule over and over again)

Now use x = 2 to find v(2) and u(2):



Then plug all these values into your expression for at x = 2