y= u^5 +u^3
u= 3/v - 4v
v= 3 - x^2
Use the chain rule in Leibniz notation to find (dy/dx) when x = 2
Text gives the solution: -48608
do i use:
(dy/dx) = (dy/du)(du/dv)(dv/dx) because when I do, I don't get the right answer.
y= u^5 +u^3
u= 3/v - 4v
v= 3 - x^2
Use the chain rule in Leibniz notation to find (dy/dx) when x = 2
Text gives the solution: -48608
do i use:
(dy/dx) = (dy/du)(du/dv)(dv/dx) because when I do, I don't get the right answer.