y= u^5 +u^3 u= 3/v - 4v v= 3 - x^2 Use the chain rule in Leibniz notation to find (dy/dx) when x = 2 Text gives the solution: -48608 do i use: (dy/dx) = (dy/du)(du/dv)(dv/dx) because when I do, I don't get the right answer.
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Originally Posted by white_cap y= u^5 +u^3 u= 3/v - 4v v= 3 - x^2 Use the chain rule in Leibniz notation to find (dy/dx) when x = 2 Text gives the solution: -48608 do i use: (dy/dx) = (dy/du)(du/dv)(dv/dx) because when I do, I don't get the right answer. you do use the chain rule, but first you have to substitute to get your function in terms of x then distrubute y= u^5 +u^3 now u can differentiate this function using the chain rule in terms of
Well take the derivative: (Just the application of the power rule over and over again) Now use x = 2 to find v(2) and u(2): Then plug all these values into your expression for at x = 2
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