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- May 1st 2008, 03:26 PM #1

- May 1st 2008, 03:31 PM #2

- May 1st 2008, 04:58 PM #3
## So far

I used the typical area formula for the triangle, then for the area of the shaded region, i constructed a rectangle, then subtracted they two triangles it formed, leaving the area of the shaded region as an integral. the hard part is the actual ratio, which is

Then one of the steps the author of my book took was to take the derivative of the numerator and the denominator separately, so it looks like this...

Don't worry about the steps to get to this because this is actually where i am having my trouble...how do you justify taking the derivative of the numerator and denominator separately and what do you do next. The answer is

- May 1st 2008, 05:10 PM #4

- May 1st 2008, 06:42 PM #5