Maclaurin series? If yes show us what you have done.
Because the series for cos has alternating signs the error for x=0.001 is less than the first neglected term. Alternativley use one of the remainder formulas for Taylor series.2. Determine the degree of the Maclauren polynomial required for the error in the approximation of the function, f(x) = cos(x) to be less than 0.001, if x=0.1