1. ## Integration

Hi I am slightly stuck with what to do for this question. Any help would be great.

curve: y= x(x-1)(x-2)

a) find the equation of the tangent at the point P whose x coordinate is 1/2

b) show that the point Q(2,0) lies on the tangent and on C

Thanks

2. 1. Remember. The derivative of a function at a particular point represents the slope. So find y' and plug in x = 1/2 to get your slope. Then, use the point slope form of a line to get your tangent line: $\displaystyle y - y_{0} = m(x - x_{0})$ where $\displaystyle (x_{0}, y_{0})$ is your point P.

2. Plug in Q(2,0) into your tangent line equation to see if there is an equality. Do the same for C.

3. Originally Posted by soso
Hi I am slightly stuck with what to do for this question. Any help would be great.

curve: y= x(x-1)(x-2)

a) find the equation of the tangent at the point P whose x coordinate is 1/2

b) show that the point Q(2,0) lies on the tangent and on C

If you mean the area bounded by the curve and the x-axis...we see the curve equals 0 at x=0. x=1, x=2...then the area of the region would be $\displaystyle \int_0^{2}|x(x-1)(x-2)|dx$