Find the surface area of revolution generated by the following curve (given in parametric form):

$\displaystyle x = cos\theta(1+cos\theta), y=sin\theta(1+cos\theta), \left(0\le\theta\le\pi\right)$.

I managed to get the following:

Surface Area = $\displaystyle 2\pi\int_0^{\pi} 2sin\theta cos\frac{\theta}{2}(1+cos\theta)d\theta $

How on Earth do I integrate this? Thanks for any help