Originally Posted by

**Jughead5267** Hey everybody, newbie here, looking for some quick help. I promised a good friend of mine help with her calculus homework, but I've gotten rusty, and only have a fleeting glimpse of what I should be doing. PLEASE HELP

Here's the functions, of which I've got to find the area within the curve.

y=x^3 - 5x + 2

y=Sqrt(2-x)

y=-Sqrt(2-x)

The graph kinda looks like a horizontal parabola & a vertical snake...

The relevant points of intersection I've found are:

(.12666695, 2.0567), (2,0), & (.69576957, -1.1420)

Of course the x-values are the only ones needed.

Thus

the upper limits for Int1 are .12666695, and .69576957

The upper limts for Int2 are .69576957, and 2

This is where I am stuck.

Do I plug them into Sqrt(2-x) - ((x^3) - 5x + 2), or have I missed a step?

It is beyond late right now, so if I could get some assistance while I sleep, I'll be eternally grateful.