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Math Help - Calculus Help!!!

  1. #1
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    Calculus Help!!!

    The error function, erf(x), is defined by the following

    .

    (a) .


    (b)

    can someon please help me out with this one...thanksness

    mathlete
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  2. #2
    o_O
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    (a)If x = 0, you have the definite integral:
    \int_{0}^{0}e^{-t^{2}}dt
    which results in?

    (b)Think of the fundamental theorem of calculus (with an added variation involving the chain rule):
    \frac{d}{dx} \int_{a}^{g(x)}f(t)dt = f\left(g(x)\right) \cdot g'(x)
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by mathlete View Post
    The error function, erf(x), is defined by the following

    .

    (a) .


    (b)

    can someon please help me out with this one...thanksness

    mathlete
    erf(0)=\frac{2}{\sqrt{\pi}}\int_0^{0}...stop

    What do you think...integral from a to a? answer...0

    secondly erf'(x^3)=\frac{d}{dx}\bigg[\int_0^{x^3}e^{-x^2}dx\bigg]

    which is 3x^2e^{-x^6}
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  4. #4
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by o_O View Post
    (a)If x = 0, you have the definite integral:
    \int_{0}^{0}e^{-t^{2}}dt
    which results in?

    (b)Think of the fundamental theorem of calculus (with an added variation involving the chain rule):
    \frac{d}{dx} \int_{a}^{g(x)}f(t)dt = f\left(g(x)\right) \cdot g'(x)
    lsdfjlkasdfjsdk ...
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