1. ## Calculus Help!!!

The error function, erf(x), is defined by the following

.

(a) .

(b)

mathlete

2. (a)If x = 0, you have the definite integral:
$\displaystyle \int_{0}^{0}e^{-t^{2}}dt$
which results in?

(b)Think of the fundamental theorem of calculus (with an added variation involving the chain rule):
$\displaystyle \frac{d}{dx} \int_{a}^{g(x)}f(t)dt = f\left(g(x)\right) \cdot g'(x)$

3. Originally Posted by mathlete
The error function, erf(x), is defined by the following

.

(a) .

(b)

mathlete
$\displaystyle erf(0)=\frac{2}{\sqrt{\pi}}\int_0^{0}...stop$

What do you think...integral from a to a? answer...0

secondly $\displaystyle erf'(x^3)=\frac{d}{dx}\bigg[\int_0^{x^3}e^{-x^2}dx\bigg]$

which is $\displaystyle 3x^2e^{-x^6}$

4. Originally Posted by o_O
(a)If x = 0, you have the definite integral:
$\displaystyle \int_{0}^{0}e^{-t^{2}}dt$
which results in?

(b)Think of the fundamental theorem of calculus (with an added variation involving the chain rule):
$\displaystyle \frac{d}{dx} \int_{a}^{g(x)}f(t)dt = f\left(g(x)\right) \cdot g'(x)$
lsdfjlkasdfjsdk ...