# Taylor Polynomials

• Apr 29th 2008, 02:46 PM
Foxtenn5
Taylor Polynomials
Determine the third Taylor Polynomial of f(x) at x=0 for the function

f(x)=(x+1)^-1/2

p(x)=1+1/2x+3/8x^2+5/16x^3

Is this correct, and is it called the third Taylor polynomial because it ends in x^3? Also, is the p(x) correct or should it be written another way?
• Apr 29th 2008, 02:50 PM
icemanfan
Quote:

Originally Posted by Foxtenn5
Determine the third Taylor Polynomial of f(x) at x=0 for the function

f(x)=(x+1)^-1/2

p(x)=1+1/2x+3/8x^2+5/16x^3

Is this correct, and is it called the third Taylor polynomial because it ends in x^3? Also, is the p(x) correct or should it be written another way?

You're not quite right. Your coefficients are correct except that two of them should be negative. But as for the degree of the polynomial, it is correct.
• Apr 29th 2008, 02:58 PM
Foxtenn5
Quote:

Originally Posted by icemanfan
You're not quite right. Your coefficients are correct except that two of them should be negative. But as for the degree of the polynomial, it is correct.

Oh, so should it be

p(x)=1-1/2x+3/8x^2-5/16x^3
• Apr 29th 2008, 03:01 PM
icemanfan
Quote:

Originally Posted by Foxtenn5
Oh, so should it be

p(x)=1-1/2x+3/8x^2-5/16x^3

Yes, that is correct.
• Apr 29th 2008, 03:06 PM
Foxtenn5
(Rofl) Thanks!!