This is the entire problem...
Use 2 repetitions of the Newton-Raphson algorithm to find the value of x near zero for which e^x=2cosx. (answer to 3 decimal places)
What I've done so far...
.....this is where I get stuck b/c my calculator says ERROR since I can't divide by 0. What am I doing wrong???
Is this how to do it?
I ended up with 0.628, but this doesn't seem to be the exact zero. (Thinking)
Yes...this is a good approximation...that is what this is...just an approximation..the actual answer is .539...but to get that you would have to do a few more iterations...this is good enough for what you were asked to do...good job (Clapping)
Originally Posted by Foxtenn5
NR gives the itteration:
Originally Posted by Mathstud28
Then five iterations give:
So after 2 iterations you have a relativly poor approximation, you realy need more iterations