I take it you mean,"the solid that is bounded above and below by the sphere and inside the cylinder ".
Polar:
Hi,
I was looking through some past papers and came across the following:
Express the volume that is contained inside both the sphere x^2+y^2+z^2=4 and the cylinder x^2+y^2=1 as a triple integral in:
1. Cartesian Co-ordinates.
2. Cylindrical Polar Co-ordinates.
Then, I am asked to evaluate (2) to find the required volume.
I am unsure how to go about answering this. I thought about writing:
z=sqrt(4-x^2-y^2).
Then, I would have a triple integral. I would integrate with respect to z first, between -sqrt(4-x^2-y^2) and +sqrt(4-x^2-y^2). Then, y between -sqrt(1-x^2) and +sqrt(1-x^2), finally x between -2 and 2. However, should I be integrating x^2+y^2-1 here?!?
I can see how the second part helps (r between 0 and 1, theta between 0 and two Pi), but I dont know how to go about writing it without the first part. I also dont know what z would be in this case.
Any help would be appreciated, i've been scratching my head on this one the last week or so now!
Hi,
Thanks for your reply. I put the question down exactly as I was asked, the first part of the question asked me to express (x,y,z) in terms of (r, theta, z), and then this was the second part of the question. I dont understand how you got to the spherical part from the polar part. I can see that r will be from 0 to 1, and theta will be from 0 to 2Pi (just by the fact we are looking at a circle and a sphere) however I dont understand how you obtained the z limits. I can see that by re-writing the sphere x^2+y^2+z^2=4 as:
z=sqrt(4-r^2)
So how come you have the limit of integration as sqrt(2-r^2)? I can see where the r comes from, the Jacobian. However, where does the '2' come from at the start of the integral?
Also, did I construct the problem in Cartesian Co-ordinates correctly?!?