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Math Help - Calculus

  1. #1
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    Calculus

    How does one find the length of y = x^3/3 + 1/(4x) from x = 1 to 2?
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  2. #2
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    Quote Originally Posted by Unenlightened View Post
    How does one find the length of y = x^3/3 + 1/(4x) from x = 1 to 2?
    The formula for arc length is s= \int_{a}^{b}\sqrt{a+f'[x]^2}dx, where the arc runs from a to b. Look familiar?
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by Unenlightened View Post
    How does one find the length of y = x^3/3 + 1/(4x) from x = 1 to 2?
    arclenght is given by \int_a^{b}\sqrt{1+f'(x)^2}dx

    so in this case it would be \int_1^{2}\sqrt{1+\bigg(x^2+\frac{-1}{(4x)^2}\bigg)^2}dx
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  4. #4
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    Cheers - it's not actually for me. A friend was asking me and I couldn't remember how to do it. We don't use numbers anymore in my course
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