Thank you =)

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- Apr 26th 2008, 06:51 AMrawrzjajaRate of change of Area in a Rectangle
Thank you =)

- Apr 26th 2008, 06:55 AMMoo
Hello,

Let $\displaystyle A$ be the area of the rectangle.

$\displaystyle A(t)=ab=(1+t^{1/3})^3 (10-\sqrt{t})^2$

What you look for is $\displaystyle \frac{dA}{dt}(64)$

So find the derivative for $\displaystyle A(t)$ and find its value at t=64. - Apr 27th 2008, 04:11 AMCaptainBlack
Another consequence of not quoting the post you are replying to is this, the blighter has deleted his/her question leaving your answer hanging. This makes it more difficult for someone else to learn from what you have done.

(Quoting also makes it more difficult for someone who is trying to cheat in maths competions or on their exams to elliminate the evidence)

RonL - Apr 27th 2008, 08:06 AMMoo
I'll do it next time (Bow)

But I've got something like 50% of accuracy when it comes to quote things :D