(1) Take derivative, find zero for dy/dx. Plug the x back in to y(x). This finds the max height.Originally Posted by Pinky&The Brain
(2) Find zero for y(x). This finds the positions when cannonball is at the ground.
I am having a hard time with this one, can anybody help?
Cannonball fired on 45 deg angle from horizontal. Initial position is origin. initial velocity 100sqrt(2) ft/sec. Trajectory is y=x-(x/25)^2 where y>=0.
How far till it hits the ground?
What's the max height?