1. Integration

$\int t^2 (1+t^2)^\frac {1}{2}dt$

How can I do this?

If I use a substitution,
u=1+t^2 => t = (u-1)^1/2

then du/dt = 2t

Then it is more complex. What to do?

2. try using u = tan x

try using u = tan x
Ya. I get it. Thanks

4. Originally Posted by geton
$\int t^2 (1+t^2)^\frac {1}{2}dt$

How can I do this?

If I use a substitution,
u=1+t^2 => t = (u-1)^1/2

then du/dt = 2t

Then it is more complex. What to do?
This is actually a very difficult integral...Deshand was right you cant use algaebraic substitution to a happy end

5. Originally Posted by geton
$\int t^2 (1+t^2)^\frac {1}{2}dt$

How can I do this?

If I use a substitution,
u=1+t^2 => t = (u-1)^1/2

then du/dt = 2t

Then it is more complex. What to do?
With trig sub you hget $\int\tan^2(\theta)\sec(\theta)d\theta$