Find the coordinates of the point(s) of intersection of the line x = 1 - t, y = 2 + 3t, z = 1 - t and the surface z = x^2 + 2y^2.
Im completely lost. My book has not example of this and I dont remember seeing a problem like this.
Find the coordinates of the point(s) of intersection of the line x = 1 - t, y = 2 + 3t, z = 1 - t and the surface z = x^2 + 2y^2.
Im completely lost. My book has not example of this and I dont remember seeing a problem like this.
Hello, kenshinofkin!
I agree with Mathstud28 . . . The problem has no solution.
Find the coordinates of the point(s) of intersection of the line: .
. . and the surface: .
The usual way is to substitute the parametric equations into the surface's equation.
Then we have: .
. . . . . . . . .
But this simplifies to: . . . . which has no real solutions.
. . The line does not intersect the elliptic paraboloid.