If dP/dt=.075P, Find a formula for P in terms of t if P(0)=500. Thanks
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Originally Posted by sandiego234 If dP/dt=.075P, Find a formula for P in terms of t if P(0)=500. Thanks $\displaystyle \frac{dP}{P}=.075dt$ integrate both sides to get $\displaystyle ln|P|=.075t+c \iff P=e^{.075t+c}=e^{c}\cdot e^{.075t}$ $\displaystyle P=Ae^{.075t}$ Just plug in the intial condition and your done.
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