The second one you have the derivative would beok help: we're given the following:

integral from 0 to 5 of f(x) = 8

f(x) is even function

integral from 0 to 5 of g(x) = 4

g(x) is odd function

find the following (if possible):

integral from 0 to 5 of [f(x)/g(x)]dx

next:

f(x) = integral from [1 to 2x] of [dt/(t^2+1)^(1/3)]

find f'(1)

(I feel as though 1/(2^(1/3)) would be too easy)

next:

let x^2 - 4xy + y^2 = 3, find expression for dy/dx

when I do it I get (2y-x)/(y-2x) where (y-x) cancel out and I just get 1 - which doesnt even make sense

then it goes on asking "are there any points on curve where tangent is horizontal or vertical?" well, obviously its a constant then ...

I have to have done something wrong

(AS WE SPEAK - WORKING ON TYPING THESE IN USING ACTUAL MATH FORM - JUST BE PATIENT, LOL)