ok help: we're given the following:

$\displaystyle \int_{0}^{5}{f(x)dx = 8}$

f(x) is even function

$\displaystyle \int_{0}^{5}{g(x)dx = 4}$

g(x) is odd function

find the following (if possible):

$\displaystyle \int_{0}^{5}\frac{f(x)}{g(x)}dx$

next:

$\displaystyle f(x) = \int_{1}^{2x}\frac{dt}{(t^2+1)^\frac{1}{3}}$

find f'(1)

(I feel as though $\displaystyle \frac{1}{2^\frac{1}{3}}$ would be too easy)

next:

let $\displaystyle {x^2 - 4xy + y^2 = 3}$, find expression for $\displaystyle \frac{dy}{dx}$

when I do it I get $\displaystyle \frac{2y-x}{y-2x}$

then it goes on asking "are there any points on curve where tangent is horizontal or vertical?"