Show that the polar curve r = 4 + 2sec(theta) has the line x = 2 as a vertical asymptote by showing that lim (r -> inf) x = 2
I don't understand what its asking for me to do, and how I should do it.
I have, however, shown that r = r + 4 without using limits, but it specifically asks for a limit.
Well, I'd like you to help me understand limits again. It's been a while since we solved for limits in class. So, does lim (r to inf) x = 2 mean that r approaches inf when x is = to 2? And if that is the case, how do I "solve" this because I am unsure how to show it. I'd think that we can plug in x = 2 but what would that do?
As much as I hate asking another similar question, this one seems harder to solve. r = sinTtanT show that it has the line x = 1 as a vertical asymptote. I assume its done the same way but I dont see how to change r solely to x as flyign squirrel described
The idea is the same, except that me use and instead :
As you are told that the asymptote is the line , you can find for which it will be reached solving . (here, the limit is useless because exists but it will not always be true) Then, check that and conclude.