$\displaystyle d^2y/dx^2 - dy/dx - dy= 3e^-x + 10sinx -4x$

please check if my answer are correct

$\displaystyle y=c1e^-x + c2e^2x -xe^-x+ cosx +3sinx+2x$

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- Apr 24th 2008, 02:47 AMtakfind the general solution ODE pls help
$\displaystyle d^2y/dx^2 - dy/dx - dy= 3e^-x + 10sinx -4x$

please check if my answer are correct

$\displaystyle y=c1e^-x + c2e^2x -xe^-x+ cosx +3sinx+2x$ - Apr 24th 2008, 03:02 AMIsomorphism
- Apr 24th 2008, 08:22 AMtakdoes it mean i have to difficentiate again
Does it mean I have to differentiate again?

- Apr 24th 2008, 08:37 AMTheEmptySet
I think we may have a problem.

$\displaystyle \frac{d^2y}{dx}-\frac{dy}{dx}-y=3e^{-x}+10\sin(x)-4x$

solving the homogenious equation for the particular solution we get..

$\displaystyle \frac{d^2y}{dx}-\frac{dy}{dx}-y=0$

$\displaystyle m^2-m-1=0 \iff m^2-m+\frac{1}{4}=1+\frac{1}{4} \iff (x-\frac{1}{2})^2=\frac{5}{4} \iff x=\frac{1 \pm \sqrt{5}}{2}$

so

$\displaystyle y_c=c_1e^{\frac{1+\sqrt{5}}{2}x}+c_2e^{\frac{1-\sqrt{5}}{2}x}$

See what you can do from here. - Apr 24th 2008, 10:29 AMtaksorry it should be 2y
$\displaystyle \frac{d^2y}{dx}-\frac{dy}{dx}-2y=3e^{-x}+10\sin(x)-4x

$

very sorry it should be 2y - Apr 24th 2008, 10:57 AMTheEmptySet
then the equation is

$\displaystyle m^2-m-2=0 \iff (m-2)(m+1)$

so

$\displaystyle y_c=c_1e^{2x}+c_2e^{-x}$

Now we need to find the particular solution

since $\displaystyle e^{-x}$ in the complimentry solution

the particular solution will be of the form

$\displaystyle y_p=\underbrace{Ax^2+Bx+C}_{forThe-4x}+\underbrace{E\cos(x)+F\sin(x)}_{forThe10\sin(x )}+\underbrace{G(e^{-x})+H(xe^{-x})}_{forTheRepeted 3 e^{-x}}$ - Apr 24th 2008, 01:42 PMtakmultiplixity one
Hi

I Know that i need to multiply by x but do I need to keep the existing term for the last part. - Apr 24th 2008, 01:55 PMtaklast part
how do you know that you need to keep the G(e^-x) term. I saw some website they don't add in and some does. Can I know th rule