hi given (2x - 4y + 5 ) * ( dy/dx ) + x - 2y + 3 = 0
I'v let u = x - 2y; dy/dx = 1-2*(dy/dx); dy/dx = 1/2 * ( 1 - du/dx )
sub into origin eqn:
( 2u + 5 ) [ 1/2 ( 1-du/dx ) ] + u + 3 = 0
( 2u + 5 ) [ 1/2 - 1/2 * du/dx ] + u + 3 = 0
( 2u + 5 ) / 2 - ( ( 2u + 5 ) / 2 ) * du/dx = -u - 3
( 2u + 5 ) du/dx = 4u + 11 ....
so how i should carry on from here? thx u!!!