Results 1 to 2 of 2

Math Help - Maximum percentage error in the estimate area of the rectangle

  1. #1
    Newbie
    Joined
    Apr 2008
    Posts
    14

    Maximum percentage error in the estimate area of the rectangle

    The length and width of a rectangle are measured as 30cm and 24 respectively. with an error measurement of at most 0.1cm in each. What is the maximum percentage error in the estimate area of the rectangle?

    How do I work this out?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Behold, the power of SARDINES!
    TheEmptySet's Avatar
    Joined
    Feb 2008
    From
    Yuma, AZ, USA
    Posts
    3,764
    Thanks
    78
    Quote Originally Posted by dangerous_dave View Post
    The length and width of a rectangle are measured as 30cm and 24 respectively. with an error measurement of at most 0.1cm in each. What is the maximum percentage error in the estimate area of the rectangle?

    How do I work this out?
    error =\frac{\Delta A}{A} \approx \frac{dA}{A}

    A(l,w)=lw

    so

     dA=A_l \Delta l + A_w \Delta w

    so we get

    dA=30cm(.1cm)+24(.1cm)cm=5.4cm^2

    error  \approx \frac{5.4cm^2}{720cm^2} = 0.0075= 0.75\%
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Estimate the percentage error
    Posted in the Calculus Forum
    Replies: 5
    Last Post: January 10th 2011, 04:09 PM
  2. Replies: 2
    Last Post: September 29th 2009, 11:05 AM
  3. Replies: 2
    Last Post: July 11th 2009, 09:09 PM
  4. Differentials to estimate the maximum error
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 27th 2009, 07:07 PM
  5. maximum error percentage
    Posted in the Calculus Forum
    Replies: 3
    Last Post: September 5th 2008, 04:22 AM

Search Tags


/mathhelpforum @mathhelpforum