Note that where s represents distance. So:
Do a substitution of:
So you get:
Can you see where you can go with the ?
Note that there will be the constant after integrating. They give you the point (0, 10) to allow you to solve for it.
Find an equation for the distance traveled by an object moving along a straight line if the velocity at time t is given by: v=1/the square root of (9-t^2). The object was 10m from the point of reference at t=0s.
I think you need to use integrals with inverse trigonometry, but im not sure. Please help!!!