Find the general antiderivative of the function below. Use theta forθ.

http://www.webassign.net/www31/symIm...49fc1a6e16.gif

P(θ) = +C

need help with another one please, just dont know where to begin, any help would be fantastic, thanks

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- Apr 23rd 2008, 11:53 AMmathleteConstructing Antiderivatives!!
Find the general antiderivative of the function below. Use theta for

*θ*.

http://www.webassign.net/www31/symIm...49fc1a6e16.gif

*P*(*θ*) = +*C*

*need help with another one please, just dont know where to begin, any help would be fantastic, thanks* - Apr 23rd 2008, 11:58 AMo_O
Some hints:

$\displaystyle \frac{d}{dx} \sec \theta = \sec \theta \tan \theta$

$\displaystyle \frac{d}{dx} \tan \theta = \sec^{2} \theta$

Can you see how these apply to your integral? Basically you're going backwards from derivatives you learned in differentiation. - Apr 24th 2008, 04:50 PMbluejewballs
- Apr 24th 2008, 04:51 PMMathstud28
- Apr 24th 2008, 04:53 PMo_O
Let me colour code this:

$\displaystyle p(\theta) = {\color{red} \sec \theta \tan \theta } + {\color{blue}\frac{6}{\cos^{2} \theta}}$

$\displaystyle \frac{d}{dx} \sec \theta = {\color{red} \sec \theta \tan \theta }$

$\displaystyle \frac{d}{dx} \tan \theta = {\color{blue}sec^{2} \theta}$**

** Should've been this one in the first post