1. ## Constructing Antiderivatives Analytically!!

Find the general antiderivative of the function below.

G(x) = + C

2. Hello,

$\frac{1}{x^3}=x^{-3}$

$\frac{1}{\sqrt{x}}=x^{-1/2}$

The antiderivative for $x^a, \forall a \in \mathbb{R}$ is $\frac{x^{a+1}}{a+1}$

3. Originally Posted by Moo
Hello,

$\frac{1}{x^3}=x^{-3}$

$\frac{1}{\sqrt{x}}=x^{-1/2}$

The antiderivative for $x^a, \forall a \in \mathbb{R}$ is $\frac{x^{a+1}}{a+1}$
Except $a=-1$ in which case it is $\ln(x)$

4. Yep