where 0 <= x <= 3 & 0 <= y <= x & 0 <= z <= x+y
Thought it'd be simple, but apparently I'm missing something because my answer isn't matching the back of the book.
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The bounds for z contain x and y, so you'll have to integrate firstly in respect with z.
Then, the bounds for y contain x, so integrate in respect with y before x.
Is it helpful ?
Hmhm, you got the same answer I did...glad I'm not alone, at least. ^^
The answer in the back of the book is 64/15.
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