use the substitution u = 2^x to find the exact value of
integral at the top it says 1 and at the bottom 0 then a fraction :
top bit = 2^x
bottom bit = (2^x = 1) squared
then in the middle at the end it says dx
use the substitution u = 2^x to find the exact value of
integral at the top it says 1 and at the bottom 0 then a fraction :
top bit = 2^x
bottom bit = (2^x = 1) squared
then in the middle at the end it says dx
Do you mean $\displaystyle \int_{0}^1 \frac{2^x}{(2^x + 1)^2} \, dx$?
Well then do as it says. Sub $\displaystyle u = 2^x \Rightarrow du = 2^x \ln 2 \, dx$