1/cot(x) is simply tan(x), so this integral is really
Use this identity and it should be easy.
Attached document contain question rearding indefinite integrals.
Can someone help to provide solution for all three questions ASAP.
Apologise for improper way of defining the question as i don't have the software in which we can draw maths problem nicely.
Thanks in advance.
_____________Originally Posted by Jameson
for this problem, i think just rewrite the function in term tanx = sinx/cosx
then, you will flip cosx into the denominator. It will come out like this, intergal of (sinx/cos^2x)dx
next step, using the sub methods
let u = cosx, du = - sinxdx
-du = sinxdx
then just jam that into the integral.
u will get something like du/u^2
bring u^2 on top : u-2
take the integral. u^-1/-1 or
1/-cosx + c will become your answer